SOLUTION: Suppose that Julian has 44 coins consisting of pennies and nickels. If the number of nickels is two more than, twice the number of pennies , find the number of coins of each kind?

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Question 533617: Suppose that Julian has 44 coins consisting of pennies and nickels. If the number of nickels is two more than, twice the number of pennies , find the number of coins of each kind?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let p = number of pennies
Let n = number of nickels
given:
(1) +n+%2B+p+=+44+
(2) +n+=+2p+%2B+2+
Substitute (2) into (1)
(1) +2p+%2B+2+%2B+p+=+44+
(1) +3p+=+44+-+2+
(1) +3p+=+42+
(1) +p+=+14+
and, since
(2) +n+=+2p+%2B+2+
(2) +n+=+2%2A14+%2B+2+
(2) +n+=+28+%2B+2+
(2) +n+=+30+
There are 14 pennies and 30 nickels