SOLUTION: how would you solve these types of proportion problems? i am confused, so please tell step by step!!! 1) x+2/5 = 4/x+1 2) 2/x-3 = x-2/6

Algebra ->  Proportions  -> Lessons -> SOLUTION: how would you solve these types of proportion problems? i am confused, so please tell step by step!!! 1) x+2/5 = 4/x+1 2) 2/x-3 = x-2/6      Log On


   

Question 474037: how would you solve these types of proportion problems? i am confused, so please tell step by step!!!

1) x+2/5 = 4/x+1
2) 2/x-3 = x-2/6
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

%28x%2B2%29%2F5+=+4%2F%28x%2B1%29  |Cross Multiplying to solve

    (x+2)(x+1) = 20

    x^2 + 3x + 2 = 20

    x^2 + 3x - 18 = 0

factoring

   (x+6)(x-3) = 0

   (x+6)=0   x= -6  Extraneous solution(CANNOT divide by zero)

   (x-3) = 0   x = highlight%283%29  AND 5/5 = 4/4 = 1 (checking out answer)



the 2nd is completed in a similar manner