Question 38564This question is from textbook college algebra
: a lake is 928 acres and has a depth of 17 feet, how may cubic feet of water is in the lake?
This question is from textbook college algebra
Found 2 solutions by KneesAndToes, AnlytcPhil:
Answer by KneesAndToes(13)   (Show Source):
You can put this solution on YOUR website! Use LxWxH to find total ft3
1 acre = 43,560 ft2 (multiply both sides by 928)
928 acres = 40,423,680 ft2 (this total is LxW)
(40,423,680 ft2)(17ft) = 687,202,560 ft3
Answer by AnlytcPhil(1806)  (Show Source):
You can put this solution on YOUR website! A lake is 928 acres and has a depth of 17 feet, how may cubic feet of water is
in the lake?
Any shape that has the same shape and area of cross-section all the way through
is a prism. The equation for calculating the volume of a prism is the cross-
sectional area of the prism multiplied by its length.
If we assume the depth everywhere is 17 feet, then the lake is a prism.
The area of the lake's cross-section, i.e., its surface is 928 acres
Since 1 Acre = 43560 ft², 928 Acres = 928×43560 ft² = 40423680 ft²
Volume = (Area of cross-section)×(height, which in this case is depth)
Volume = 40423680 ft² × 17 ft = 687202560 ft³
Edwin
AnlytcPhil@aol.com
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