SOLUTION: Laura invested $2000. Some at 8% per year and the rest at 10% giving her a total income of $176 per year. How much money did she invest at 8%.
I know that I need to create a t
Algebra ->
Proportions
-> Lessons
-> SOLUTION: Laura invested $2000. Some at 8% per year and the rest at 10% giving her a total income of $176 per year. How much money did she invest at 8%.
I know that I need to create a t
Log On
Question 37315This question is from textbook
: Laura invested $2000. Some at 8% per year and the rest at 10% giving her a total income of $176 per year. How much money did she invest at 8%.
I know that I need to create a table. I'm stuck as to what to do next. I appreciate your help and thanks so much!
Amount invested x Rate = Interest
Investment A 2000 7% .07(2000)
Investment B
Total Investment 176 This question is from textbook
You can put this solution on YOUR website! .08X+.1(2000-X)=176 OR .08X+200-.1X=176 OR -.02X=-24 OR X=24/.02 OR X=1200 THUS 1200 WAS INVESTED @ 8% WHILE 2000-1200=800 INVESTED @ 10%
PROOF.08*1200+.1*800=176 OR 96+80=176 OR 176=176
INVESTMENT A 1200@8%=$96
INVESTMENT B 800*10%=$80
TOTAL INVESTMENT $176
(