SOLUTION: Dave and Cindy played 53 games of backgammon last month. Dave's ratio of wins to losses was 37/16. If Dave and Cindy play 10 more games, write a proportion to determine how many

Algebra ->  Proportions  -> Lessons -> SOLUTION: Dave and Cindy played 53 games of backgammon last month. Dave's ratio of wins to losses was 37/16. If Dave and Cindy play 10 more games, write a proportion to determine how many       Log On


   

Question 364913: Dave and Cindy played 53 games of backgammon last month. Dave's ratio of wins to losses was 37/16.
If Dave and Cindy play 10 more games, write a proportion to determine how many of these 10 games dave could expect to win.
Determine how many more games Dave and Cindy must play before Cindy will have won a total of 28 games.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Dave and Cindy played 53 games of backgammon last month.
Dave's ratio of wins to losses was 37/16.
If Dave and Cindy play 10 more games, write a proportion to determine how many
of these 10 games dave could expect to win.
:
If the proportion remains the same for these 10 games:
37%2F53 * 10 ~ 7 games
:
:
Determine how many more games Dave and Cindy must play before Cindy will have
won a total of 28 games.
Let x = no. of additional games for this to happen
16%2F53 = 28%2F%28%28x%2B53%29%29
Cross multiply
16(x+53) = 28 * 53
16x + 848 = 1484
16x = 1484 - 848
x = 636%2F16
x ~ 40 more games
:
:
Check this:
original per cent: 16/53 ~ .3
40 more games percent: 28/93 ~ .3