SOLUTION: Hello, I need some help. 1. How many milliliters per hour would be required to infuse a dopamine dose of 5 mcg/kg/min to a patient weighing 220 lb. If the dopamine is provided b

Algebra ->  Proportions  -> Lessons -> SOLUTION: Hello, I need some help. 1. How many milliliters per hour would be required to infuse a dopamine dose of 5 mcg/kg/min to a patient weighing 220 lb. If the dopamine is provided b      Log On


   



Question 22931: Hello, I need some help.
1. How many milliliters per hour would be required to infuse a dopamine dose of 5 mcg/kg/min to a patient weighing 220 lb. If the dopamine is provided by a bag containing 800 mg/500ml?

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not completely sure about this one, but I'll give it a shot! (Was that a pun??)

5 mcg/kg/min would imply that we need to multiply by the number of kg of the patient, and then multiply by 60 since the question asks for an amount per hour. The patient weighs 220 lb, which if I recall correctly would be 100 kg.

5 mcg/kg/min*100 kg*60 min/hr = 30,000 mcg/hr.

In metric system you can convert to the larger units of mg, by moving the decimal three places to the left giving 30 mg/hour.

Now, I'd set up a ratio of
%28800+mg%29%2F%28500+ml%29+=+%2830+mg%29%2F%28x+ml%29

This can be simplified to 8%2F5=30%2Fx

Since a%2Fb=c%2Fd means that ad=bc, it follows that
8%2F5=30%2Fx means that 8x=5%2A30 and x+=+150%2F8+=+18.75 ml/hr.

Most math teachers, including ME, don't do much with this. I did try to do a lesson on my website on METRIC SYSTEM and DOSAGES. Probably nobody knows about it, but it's there if you care to take a look at it.

Go to my website by clicking on my tutor name "rapaljer" anywhere on algebra.com. Then look for a page in the second column called "Tech Prep", and go to "Metric System". Buried way down in that page in which I tried to show how simple the Metric System is, there is a section on Medical Dosages that might or might not be helpful. Let me know what you think!

R^2 at SCC