SOLUTION: need help with this problem!! The ratio of Alex's cycling speed to Bart's cycling speed is 6:5. Bart leaves school at 3:00 pm and alex leaves at 3:10 pm. By 3:30, Alex is only 2 k

Algebra ->  Proportions  -> Lessons -> SOLUTION: need help with this problem!! The ratio of Alex's cycling speed to Bart's cycling speed is 6:5. Bart leaves school at 3:00 pm and alex leaves at 3:10 pm. By 3:30, Alex is only 2 k      Log On


   

Question 120601This question is from textbook algebra: structure and Method: book 1
: need help with this problem!! The ratio of Alex's cycling speed to Bart's cycling speed is 6:5. Bart leaves school at 3:00 pm and alex leaves at 3:10 pm. By 3:30, Alex is only 2 km behind Bart. How fast is each boy going? PLEASE HELP!!! I AM SORRY IF THIS ISN'T ENOUGH INFO, BUT THAT IS ALL THAT IS IN THE BOOK!!!!!! This question is from textbook algebra: structure and Method: book 1

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
"The ratio of Alex's cycling speed to Bart's cycling speed is 6:5"
__ let 6x=Alex, so 5x=Bart

Bart travels for 1/2 hr (30 min) and Alex travels for 1/3 hr (20 min)
__ Bart goes 2 km farther
__ rate times time equals distance

6x(1/3)+2=5x(1/2) __ 2x+2=2.5 x __ 2=.5x