SOLUTION: If mark gives john 6 apples, mark will have 2/3 of the apples that john will have.
Now if jaime gives 9 apples to mark then john will have 2/3 of the apples
that mark will help
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-> SOLUTION: If mark gives john 6 apples, mark will have 2/3 of the apples that john will have.
Now if jaime gives 9 apples to mark then john will have 2/3 of the apples
that mark will help
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Question 1168371: If mark gives john 6 apples, mark will have 2/3 of the apples that john will have.
Now if jaime gives 9 apples to mark then john will have 2/3 of the apples
that mark will help. How many apples eache have? Found 3 solutions by CubeyThePenguin, MathTherapy, ikleyn:Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! If mark gives john 6 apples, mark will have 2/3 of the apples that john will have. Now if jaime gives 9 apples to mark then john will have 2/3 of the apples that mark will help. How many apples eache have?
Doesn't the other person know that apples are in INTEGER-form, and NOT FRACTIONAL-form? Apparently NOT!!
Needless to say, he/she is WRONG!!
Correct answer:
You can put this solution on YOUR website! .
If Mark gives John 6 apples, Mark will have 2/3 of the apples that John will have.
Now if JOHN gives 9 apples to Mark then John will have 2/3 of the apples
that Mark will HAVE. How many apples each HAS ?
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These "virtual exchange" problems all have a standard setup.
M - 6 = (1) (If mark gives john 6 apples, mark will have 2/3 of the apples that john will have)
= J - 9. (2) (if John gives 9 apples to Mark then John will have 2/3 of the apples that Mark will have)
Simplify these equations
3M - 18 = 2*(J+6) (1')
2*(M + 9) = 3*(J-9) (2')
Simplify more
3M - 2J = 30 (1'')
2M - 3J = -45 (2'')
Prepare for elimination
6M - 4J = 60 (1''')
6M - 9J = -135 (2''')
Subtract (2''') from (1''')
5J = 60 - (-135) = 195
J = 195/5 = 39.
Finally, from (1'') find M = 36.
ANSWER. M = 36; J = 39.