SOLUTION: Find b:a, from the equation 12a^2-25ab+7b^2 =0 given that the b/a is a proper fraction?

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Question 1111218: Find b:a, from the equation 12a^2-25ab+7b^2 =0 given that the b/a is a proper fraction?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
12a%5E2-25ab%2B7b%5E2+=0
12a%5E2+-21ab-4ab%2B7b%5E2=0
3a%284a-7b%29-b%284a-7b%29=0
%283a-b%29%284a-7b%29+=0
either (3a-b) =0 or (4a-7b)=0
3a-b=0
3a=b
a/b =1/2
Or
4a-7b=0
4a=7b
a/b = 7/4
choose one which is a proper fraction