SOLUTION: Find four numbers proportional to the numbers 2, 4, 5, and 6 if the difference between the sum of the two last numbers and the sum of the first two numbers is equal to 4.8.

Algebra ->  Proportions  -> Lessons -> SOLUTION: Find four numbers proportional to the numbers 2, 4, 5, and 6 if the difference between the sum of the two last numbers and the sum of the first two numbers is equal to 4.8.      Log On


   

Question 1104149: Find four numbers proportional to the numbers 2, 4, 5, and 6 if the difference between the sum of the two last numbers and the sum of the first two numbers is equal to 4.8.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Let the numbers be represented by 2x, 4x, 5x, and 6x. Then the given condition says
%286x%2B5x%29-%284x%2B2x%29+=+4.8
11x-6x=4.8
5x=4.8
x+=+.96

Then the numbers are
2x = 1.92
4x = 3.84
5x = 4.80
6x = 5.76