SOLUTION: http://prntscr.com/a8z5eq So, I figured out 24 meters for a using the altitude is the mean of the segments of a triangle theorem. However, I can't figure out what to do for b. My

Algebra ->  Proportions  -> Lessons -> SOLUTION: http://prntscr.com/a8z5eq So, I figured out 24 meters for a using the altitude is the mean of the segments of a triangle theorem. However, I can't figure out what to do for b. My       Log On


   



Question 1022390: http://prntscr.com/a8z5eq
So, I figured out 24 meters for a using the altitude is the mean of the segments of a triangle theorem. However, I can't figure out what to do for b. My teacher does NOT want us to use the Pythagorean theorem for this. In fact, we haven't even learned it yet (it comes later in the course). The only things we've learned helping us up to answer this problem is geometric mean, the theorem I just mentioned, angle-bisector-theorem, and the theorem that say the altitude of the hypotenuse of a right triangle separates the hypotenuse so that the length of each leg of the triangle is the geometric mean of the length of the hypotenuse and and the length of the segment of the hypotenuse adjacent to the leg. She wants us to work off of all or a few of those theorems, but I just can't just to figure it out.

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
Altitude ratio
:
32/altitude = altitude/18
:
Altitude = square root (576) = 24
Spot on the beach is 24m from the parking lot
:
Hypoteuse/leg = leg/projection
50/x = x/32
x = square root (1600) = 40
Refreshment stand is 40m from the parking lot
: