Question 935049: solve the system using any method 2x-3y+4z=1, x+2y+z=10, 3y-z=8
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve the system using any method
2x-3y+4z=1
x+2y+z=10
3y-z=8
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z = 3y-8
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Substitute into the 1st and 2nd equation to get:
2x - 3y + 4(3y-8) = 1
2x - 3y + 12y - 32 = 1
2x + 9y = 33
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x + 2y + 3y-8 = 10
x + 5y = 18
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You now have a 2-variable system::
x + 5y = 18
2x+ 9y = 33
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Modify for elimination::
2x + 10y = 36
2x + 9y = 33
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Subtract and solve for "y"::
y = 3
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Solve for "x" using x + 5y = 18
x + 15 = 18
x = 3
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Solve for "z" usng z = 3y-8
z = 3*3-8
z = 1
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Ans:: (3,3,1)
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Cheers,
Stan H.
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