SOLUTION: solve algebraically x^2-4y^2=16 2y-x=2

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Question 931593: solve algebraically
x^2-4y^2=16
2y-x=2
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve algebraically
x^2-4y^2=16
2y-x=2
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x = 2y-2
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Substitute for "x" and solve for "y":
(2y-2)^2 - 4y^2 = 16
4y^2 - 8y + 4 - 4y^2 = 16
8y = 4-16
8y = -12
y = -3/2
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Solve for "x":
x = 2y-2
x = 2(-3/2)-2
x = -5
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Cheers,
Stan H.
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