SOLUTION: i have to factor {{{ 2x^2 + 18x - 90 }}} i used the a-c metod but there was nothing in common for -180 and 18 so i used the gcf method and divided by 2 so i got {{{2(x^2 + 9x

Algebra ->  Test -> SOLUTION: i have to factor {{{ 2x^2 + 18x - 90 }}} i used the a-c metod but there was nothing in common for -180 and 18 so i used the gcf method and divided by 2 so i got {{{2(x^2 + 9x      Log On


   



Question 89001: i have to factor
+2x%5E2+%2B+18x+-+90+
i used the a-c metod but there was nothing
in common for -180 and 18 so i used the gcf
method and divided by 2 so i got 2%28x%5E2+%2B+9x+-+45%29
and i still could not find anything in common
for -45 and 9.

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!

i have to factor 
2x%5E2+%2B+18x+-+90
i used the a-c metod but there was nothing
in common for -180 and 18 so i used the gcf 
method and divided by 2 so i got 2%28x%5E2+%2B+9x+-+45%29 
and i still could not find anything in common 
for -45 and 9.

LOL. You just didn't know when to stop!

2x%5E2+%2B+18x+-+90

factors just as you had it:

2%28x%5E2+%2B+9x+-+45%29

It doesn't factor further, because as you said, there
are no two positive integers with product 45 and 
difference 9.  But you DID factor it, because taking 
out a common factor IS factoring.  You just thought 
it had to factor further. 

Incidentally, I noticed you tried the a-c method
first.  When you have a trinomial, don't try the 
a-c method first. Instead look for a common
factor first, and only when there isn't a common
factor should you try the a-c method.

Edwin