SOLUTION: Can anyone help me? An experimental rocket is launched into the air from ground level with the Earth with an initial velocity of 192 feet per second. Its height s in feet is giv

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Question 873018: Can anyone help me?
An experimental rocket is launched into the air from ground level with the Earth with an initial velocity of 192 feet per second. Its height s in feet is given by the formula
s=-16t^2+ 192t
After how many seconds will the rocket reach a height of 576 feet?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
576 = -16t^2 + 192t
16t^2 - 192t + 576 = 0
t^2 - 12t + 36 = 0
(t-6)(t-6)= 0 , t = 6sec