SOLUTION: A cube with edge of length 4cm is divided into 8 identical cubes. How much greater is the combined surface area of 8 smaller cubes than the surface area of the original cube
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Question 847525: A cube with edge of length 4cm is divided into 8 identical cubes. How much greater is the combined surface area of 8 smaller cubes than the surface area of the original cube Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A cube with edge of length 4cm is divided into 8 identical cubes. How much greater is the combined surface area of 8 smaller cubes than the surface area of the original cube
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Area of 4 cm = 6*4^2 = 96 sq cm
Area of 2 cm cube = 6*2^2 = 24 sq cm
8 of the 2 cm cubes --> 8*24 = 192 sq cm
96 sq cm greater, or 100% greater
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It's 2 times the area = 1 times greater.
