SOLUTION: I need help on this problem please! 3^2 + (-2)^3+ (4^2-5)

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Question 828372: I need help on this problem please!
3^2 + (-2)^3+ (4^2-5)
Found 2 solutions by KMST, MathTherapy:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
3%5E2+%2B+%28-2%29%5E3%2B+%284%5E2-5%29 has 3 terms:
3%5E2 , %28-2%29%5E3 , and %284%5E2-5%29 ,
separated by signs indicating addition.
According a very widely accepted old convention, addition and subtraction are the last operations we do when more than one operation is indicated (except as directed by parentheses).
Evaluating terms 3%5E2 , and %28-2%29%5E3 is straight forward.
Term %284%5E2-5%29 is wrapped in parentheses for no good reason.
In this particular case, the expressions with and without those parentheses are equivalent.
However, I will pretend I don't know that and I will calculate what's inside the parentheses first.
4%5E2-5 is calculated by evaluating 4%5E2 first and subtracting 5 after that.

All in all,
3%5E2+%2B+%28-2%29%5E3%2B+%284%5E2-5%29=9%2B4%2B%2816-5%29=9%2B4%2B9=highlight%2822%29

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
I need help on this problem please!
3^2 + (-2)^3+ (4^2-5)


3%5E2+%2B+%28-+2%29%5E3+%2B+%284%5E2+-+5%29

9+%2B+%28-+8%29+%2B+%2816+-+5%29

9 - 8 + 11, or highlight_green%2812%29

You can do the check!! 



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