SOLUTION: A 30% solution is prepared by mixing a 20% and 45% solution. How many litres of each must be used to produce 60 litres of the 30% solution?

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Question 770077: A 30% solution is prepared by mixing a 20% and 45% solution. How many litres of each must be used to produce 60 litres of the 30% solution?
Found 2 solutions by lwsshak3, josmiceli:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
A 30% solution is prepared by mixing a 20% and 45% solution. How many litres of each must be used to produce 60 litres of the 30% solution?
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let x=amt of 20% solution to be used
60-x=amt of 45% solution to be used
..
20%x+45%(60-x)=60%*30
0.20x+27-0.45x=18
0.25x=9
x=36
60-x=24
amt of 20% solution to be used=36 litres
amt of 45% solution to be used=24 litres

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 20% solution needed
Let +b+ = liters of 45% solution needed
+.2a+ = concentrated part of 20% solution
+.45b+ = concentrated part of 45% solution
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(1) +a+%2B+b+=+60+
(2) +%28+.2a+%2B+.45b+%29+%2F+60+=+.3+
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(2) +.2a+%2B+.45b+=+18+
(2) +20a+%2B+45b+=+1800+
Multiply both sides of (1) by +20+
and subtract (1) from (2)
(2) +20a+%2B+45b+=+1800+
)1) +-20a+-+20b+=+-1200+
+25b+=+600+
+b+=+24+
and, since
(1) +a+%2B+b+=+60+
(1) +a+=+60+-+24+
(1) +a+=+36+
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36 liters of 20% solution are needed
24 liters of 45% solution are needed