Question 766969: find the equation of a line with a y-intercept of 3 and goes through (-2,1)
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! Since the y-intercept is 3, then (0,3) is another point on the line.
y - y1
------ = slope
x = x1
(0,3) and (-2,1) are two points on the line
1 - 3
------ = slope
-2 - 0
-2
--- = slope
-2
slope = 1
Point is (-2,1) and slope is 1
Point-slope form for the equation of a line is y - y1 = m(x - x1
(x1,y1) are the coordinates of the point
m is the slope
y - 1 = 1[x - (-2)] {substituted point and slope into point-slope form}
y - 1 = x + 2 {simplified}
y = x + 3 {added 1 to each side}
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