Question 761853: Find the vertex and axis of symmetry of the graph of the fuction f(x) = 3x^2 - 2x + 5 I can't figure this one out Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the vertex and axis of symmetry of the graph of the function
f(x) = 3x^2 - 2x + 5
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3(x^2 - (2/3)x + ?) = y - 5 + 3*?
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3(x^2 - (2/3)x + (1/3)^2) = y - 5 + 3(1/3)^2
3(x-(1/3))^2 = y - (14/3)
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Vertex: (1/3 , 14/3)
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Axis of symmetry: x = 1/3
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Cheers,
Stan H.
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