SOLUTION: Can you help me solve this equation? y^2+3y=36-2y Please help!! Thank you!

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Question 744498: Can you help me solve this equation? y^2+3y=36-2y Please help!! Thank you!
Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y^2+3y=36-2y
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y^2 + 5y -36 = 0
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Factor:
y^2 + 9y-4y -36 = 0
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y(y+9)-4(y+9) = 0
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(y+9)(y-4) = 0
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y = -9 or y = 4
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Cheers,
Stan H.
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Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
y%5E2%2B3y=36-2y
+2y +2y
y%5E2%2B5y=36
-36-36
y%5E2%2B5y-36=0

y%5E2%2B9y-4y%2B36=0

y%28y%2B9%29-4%28y%2B9%29=0

%28y%2B9%29%28y-4%29=0
y=-9 OR 4