SOLUTION: the perimiter of a rectangle is 96 inches the length is 3 more then twice the width. find the dimension

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Question 740076: the perimiter of a rectangle is 96 inches the length is 3 more then twice the width. find the dimension
Found 2 solutions by lynnlo, ikleyn:
Answer by lynnlo(4176) About Me  (Show Source):
Answer by ikleyn(53354) About Me  (Show Source):
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the highlight%28cross%28perimiter%29%29 perimeter of a rectangle is 96 inches the length is 3 more highlight%28cross%28then%29%29 than twice the width.
find the dimension
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x = the width
2x+3 = the length.


The perimeter equation

    x + (2x+3) + x + (2x+3) = 96  inches

    6x + 6 = 96

    6x = 96 - 6

    6x =   90

     x =   90/6 = 15.


ANSWER.  The width is 15 inches;  the length is  2*15+3 = 33 inches.

Solved.