SOLUTION: The bulletin board is 6 ft wide and 4 feet tall. The border is 3 inches wide. What are the dimensions inside the border?

Algebra ->  Test -> SOLUTION: The bulletin board is 6 ft wide and 4 feet tall. The border is 3 inches wide. What are the dimensions inside the border?      Log On


   

Question 723017: The bulletin board is 6 ft wide and 4 feet tall. The border is 3 inches wide. What are the dimensions inside the border?
Answer by 119078(26) About Me  (Show Source):
You can put this solution on YOUR website!
Write and draw down what you know:
outside: length=6ft width=4ft
inside: length=6ft-6in width=4ft-6in (It is 6in because the board goes on both top and bottom, if you only took off 3 inches from the outside then the boarder would 1.5 inches thick)
Next make all them inches!
%286ft%2F1%29%2A%2812in%2F1ft%29 using these conversion factor you can cross out the ft and multiply across. you can also just multiple 6ft to 12in but this just sounds smart :).
After turning everything to inches you should get
Outside: l=72in w=48in
Inside: l=72in-6in= 66in w=48in-6in= 42in
Now you can find the area and perimeter of the inside rectangle (bulletin board same difference)
A=66%2A42=2772in P=%282%2A66%29%2B%282%2A42%29=216in
You can change this back to ft by conversion factors
%282772in%2F1%29%2A%281ft%2F12in%29=231ft %28216in%2F1%29%2A%281ft%2F12in%29=18ft
Area= 2772in or 231ft
Perimeter= 216in or 18ft
I hope this step by step will help you in the future with this kind of stuff. Just remember to list what you have and see what you can find first and NEED to find first.