Question 720433: I must find the horizontal and vertical asymptotes of : f(x) = x/ x^2 - 9 Found 2 solutions by lwsshak3, lynnlo:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! I must find the horizontal and vertical asymptotes of : f(x) = x/ x^2 - 9
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When the degree of the numerator is 1 less than the degree of the denominator, as in this case, the horizontal asymptote is the x-axis or y=0.
Vertical asymptotes are found by setting the denominator=0, then solving for x-values which makes the function undefined.
x^2-9=0
(x+3)(x-3)=0
x≠3
and
x≠-3
horizontal asymptotes: x-axis
Vertical asymptotes: x=3, x=-3)
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