SOLUTION: I can't figure this question out:
The area of a rectangle is 256 m. The length of the rectangle is 4 times greater than the width. What are the length and width of the triangle.
Algebra ->
Test
-> SOLUTION: I can't figure this question out:
The area of a rectangle is 256 m. The length of the rectangle is 4 times greater than the width. What are the length and width of the triangle.
Log On
Question 701863: I can't figure this question out:
The area of a rectangle is 256 m. The length of the rectangle is 4 times greater than the width. What are the length and width of the triangle. Found 2 solutions by Simnepi, solver91311:Answer by Simnepi(216) (Show Source):
You can put this solution on YOUR website! let the width of the rectangle be called x.
since the length is 4 times the width, the length will be 4x.
Now, area = length times width for a rectangle.
so the area of this rectangle, 256 square metres, is 4x times x, that is
dividing by 4 gives
to find x we have to 'undo' the squaring of x by taking the square root.
so
therefore x = 8.
which means that the width is 8m and the length is 32m
And no one else can figure it out either; not without guessing as to what you want anyway. You give area data and a relationship between the length and width of a rectangle, and then ask for "the length and width of the triangle" Triangles don't have a length and width, and I can't tell anything about a triangle given data about a rectangle unless you have established some sort of relationship between your triangle and your rectangle.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
