Question 69464:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
what is the SMALLEST positive integer such that when it is divided by 4,by 5, and by 6, it will always leave a remainder of 3?
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the prime factor form of each of the divisors is
4=2^2
5=5
6=2*3
The lcm (least common multiple) of these forms is 2^2*5*3=60
That is the SMALLEST number that 4,5, and 6 divide evenly.
To have a remainder of 3, add 3 to 60.
Answer: 63
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Cheers,
Stan H.
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