SOLUTION: Solve for w by factoring. w^2 – 4w – 5 = 0

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Question 689931: Solve for w by factoring.
w^2 – 4w – 5 = 0

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1)
In order to factor 1%2Ax%5E2%2B-4%2Ax%2B-5, first we need to ask ourselves: What two numbers multiply to -5 and add to -4? Lets find out by listing all of the possible factors of -5


Factors:

1,5,

-1,-5,List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to -5.

(-1)*(5)=-5

Now which of these pairs add to -4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -4

||
First Number|Second Number|Sum
1|-5|1+(-5)=-4
-1|5|(-1)+5=4
We can see from the table that 1 and -5 add to -4.So the two numbers that multiply to -5 and add to -4 are: 1 and -5 Now we substitute these numbers into a and b of the general equation of a product of linear factors which is: %28x%2Ba%29%28x%2Bb%29substitute a=1 and b=-5 So the equation becomes: (x+1)(x-5) Notice that if we foil (x+1)(x-5) we get the quadratic 1%2Ax%5E2%2B-4%2Ax%2B-5 again