SOLUTION: The perimiter of a rectangle is 38 units. Two sides are X, the other two are 2X - 5. How do I find X?

Algebra ->  Test -> SOLUTION: The perimiter of a rectangle is 38 units. Two sides are X, the other two are 2X - 5. How do I find X?      Log On


   



Question 658860: The perimiter of a rectangle is 38 units. Two sides are X, the other two are 2X - 5. How do I find X?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
The perimiter of a rectangle is 38 units. Two sides are X, the other two are 2X - 5. How do I find X?
.
perimeter = total length of all four sides
38 = x + x + 2x-5 + 2x-5
38 = x + x + 2x + 2x-10
38 = 6x-10
48 = 6x
8 = x
.
answer: 8 units