SOLUTION: Professor I'm having trouble with solving absolute value equations and inequalities. Hopefully this is clear. /z-2/ > 0
(A) - infinity, +infinity. (B) 0 (C) 2,-2 or (D) - infi
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(A) - infinity, +infinity. (B) 0 (C) 2,-2 or (D) - infi
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Question 647543: Professor I'm having trouble with solving absolute value equations and inequalities. Hopefully this is clear. /z-2/ > 0
(A) - infinity, +infinity. (B) 0 (C) 2,-2 or (D) - infinity, 2 and 2, infinity Answer by swincher4391(1107) (Show Source):
You can put this solution on YOUR website! = and
i)
ii)
Recall when dividing or multiplying by a negative number, it switches the way the inequality points.
So we have that z<2 and z>2. The answer may be clearer if we put this in interval notation.
So z exists in (-infinity,2) U (2,infinity). U is the union of sets symbol.
D.
