SOLUTION: A cannon fires a projectile out at a muzzle speed of 195 m/s. If the angle of the cannon is set to 45 degrees (measured from the horizontal), how far horizontally will the projec

Algebra ->  Test -> SOLUTION: A cannon fires a projectile out at a muzzle speed of 195 m/s. If the angle of the cannon is set to 45 degrees (measured from the horizontal), how far horizontally will the projec      Log On


   

Question 630379: A cannon fires a projectile out at a muzzle speed of 195 m/s. If the angle of the cannon is set to 45 degrees (measured from the horizontal), how far horizontally will the projectile it fires travel before impacting the ground? Assume that the cannon's muzzle and the ground are at the same height.
Use the Range Equation to solve this problem.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A cannon fires a projectile out at a muzzle speed of 195 m/s. If the angle of the cannon is set to 45 degrees (measured from the horizontal), how far horizontally will the projectile it fires travel before impacting the ground? Assume that the cannon's muzzle and the ground are at the same height.
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The vertical component is
v = 195%2Asqrt%282%29%2F2+ m/sec
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You didn't give info on gravity, so I'll assume it's on Earth and use
h(t) = -4.9t^2 + vt
h%28t%29+=+-4.9t%5E2+%2B+195%2Asqrt%282%29t%2F2
Find the times when h(t) = 0
h%28t%29+=+-4.9t%5E2+%2B+195%2Asqrt%282%29t%2F2+=+0
t = 0 when it's fired
t+=+195%2Asqrt%282%29%2F9.8 seconds at impact
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The horizontal component of the muzzle velocity = v also, same as vertical
d = r*t
d = %28195%2Asqrt%282%29%2F2%29%2A195sqrt%282%29%2F9.8
d = 195^2/9.8 meters
d =~ 3880 meters