SOLUTION: secA+tanA= 4, then find sinA
Algebra
->
Test
-> SOLUTION: secA+tanA= 4, then find sinA
Log On
Test Calculators and Practice
Test
Answers archive
Answers
Word Problems
Word
Lessons
Lessons
Click here to see ALL problems on test
Question 623387
:
secA+tanA= 4, then find sinA
Answer by
Alan3354(69443)
(
Show Source
):
You can
put this solution on YOUR website!
secA+tanA= 4, then find sinA
-----------
secA+tanA= 4
1/cos + sin/cos = 4
Square both sides
sin^2 + 2sin + 1 = 16 - 16sin^2
17sin^2 + 2sin - 15 = 0
Sub x for sin(A)
Solved by
pluggable
solver:
SOLVE quadratic equation (work shown, graph etc)
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
Discriminant d=1024 is greater than zero. That means that there are two solutions:
.
Quadratic expression
can be factored:
Again, the answer is: 0.882352941176471, -1. Here's your graph:
sin = -1
The -1 solution can't be used - the secant is undefined.
==============
sin =~ 0.882353