SOLUTION: Hi, I would like some help with this problem:
Two cards are drawn without replacement from a standard deck of cards.Find the following probabilities:
a) both cards are diamonds
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-> SOLUTION: Hi, I would like some help with this problem:
Two cards are drawn without replacement from a standard deck of cards.Find the following probabilities:
a) both cards are diamonds
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Question 621761: Hi, I would like some help with this problem:
Two cards are drawn without replacement from a standard deck of cards.Find the following probabilities:
a) both cards are diamonds
b) the second is a club, given that the first is a club
c) the second card is a 9, given that the first card was a 3
Thank you for your help!! Found 2 solutions by solver91311, ewatrrr:Answer by solver91311(24713) (Show Source):
a) The probability of drawing a diamond on the first draw is 13/52 or 1/4. But on the second draw, given that the first was a diamond, the probability is 12/51. These are two independent events so the total probability is the product of the two individual probabilities.
John
My calculator said it, I believe it, that settles it
Hi,
Two cards are drawn without replacement from a standard deck of cards
P(both diamonds) =
P(2nd club, given 1st is club) = 12/51
P(A|B) = P(A and B)/P(B) =
P(2nd is a 9, given 1st was a 3) = 4/51
P(A|B) = P(A and B)/P(B) =
