SOLUTION: A roller skating rink charges an admission fee of $5 for members and $10 for non-members. One day it made at least $300. Which of these combinations could have come that day?

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Question 610819: A roller skating rink charges an admission fee of $5 for members and $10 for non-members. One day it made at least $300. Which of these combinations could have come that day?
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--
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You did not include the combinations, so I cannot tell you which one would satisfy your constraints. Here is how you can solve the problem for yourself.
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I. Write an inequality to model your situation.
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Let m be the number of members.
Let n be the number of non-members.
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The expression 5x represents the amount of money paid by all the members that day.
The expression 10n represents the amount of money paid by all the non-members that day.
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The phrase "at least $300" can be written as "greater than or equal (>=) to 300." Our inequality is
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[money paid by members] + [money paid by non-members] >=[$300]
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5m%2B10n%3E=300
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Take each combination you were given in the problem and substitute the number of member and non-members int the inequality. If the inequality is true, that combination works.
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Here's an example that works: 30 members and 20 non-members. So, m=30 and n=20
5m%2B10n%3E=300
5%2830%29%2B10%2820%29%3E=300
150%2B200%3E=300
350%3E=300
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The skating rink took in $350 which is greater than or equal to $300, so that combination works.
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Feel free to email if you still have questions.
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Good luck,
Ms.Figgy
math-in-the-vortex@gmil.com