If you consider all of the possibilities for various combinations of things taken at a time and listed them in desceding order of , you would get a list that looks like:
(Since , these two list items must be equidistant from the middle item in the list.)
But since the s must all be integers, there can only be one item in the list between 7 and 5, namely
hence
So
John
My calculator said it, I believe it, that settles it
You can put this solution on YOUR website! Use the identity that C(n, k) = C(n, n-k). Here, we can let k = 5, n - k = 7. From here we get n - 5 = 7, n = 12.