SOLUTION: find eqation in standard of the lines through ponit P that are (a) parallel to , and (b)perpendicular to , line L. P(2,0); L: x+2y=3

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Question 54033This question is from textbook algebra and trigonomerty structure and method - book 2
: find eqation in standard of the lines through ponit P that are (a) parallel to , and (b)perpendicular to , line L.
P(2,0); L: x+2y=3 This question is from textbook algebra and trigonomerty structure and method - book 2

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
P(2,0);L(x+2y=3)
First put L in slope intercept form:highlight%28y=mx%2Bb%29; m=slope; (0,b)=y-intercept
x%2B2y=3
-x%2Bx%2B2y=-x%2B3
2y=-x%2B3
2y%2F2=-x%2F2%2B3%2F2
y=%28-1%2F2%29x%2B3%2F2
L has a slope of -1/2.
(a)Parallel lines have the same slopes, so the new line has a slope of -1/2 also.P(2,0)=(x1,y1)
Use the point slope formula highlight%28y-y1=m%28x-x1%29%29 to find the equation of the line:
y-0=-1%2F2%28x-2%29
highlight%28y=%28-1%2F2%29x%2B1%29
(b) Perpendicular lines have slopes that are negative reciprocals of each other. So flip -1/2 over and change the sign and your new line will have a slope m=2/1 or m=2. P(2,0) Use the point slope formula to find the equation of the line again.
y-0=2%28x-2%29
highlight%28y=2x-4%29
Happy Calculating!!!