Question 524148: Find an equation for the line with the given properties. Express the equation in slope-intercept form.
Containing the points P=(-2,1) and Q=(-1,-1)
Found 3 solutions by stanbon, oberobic, solver91311:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Express the equation in slope-intercept form.
Containing the points P=(-2,1) and Q=(-1,-1)
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slope = (-1-1)/(-1--2) = -2/1 = -2
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Form y = mx +b
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You know m = -2 and y = 1 when x = -2.
Solve for "b";
1 = -2*-2 + b
b = -3
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Equation:
y = -2x-3
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Cheers,
Stan H.
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Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! m = (1-(-1)) / (-2-(-1))
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m = 2 / -1
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m = -2 = slope
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y = -2x + b
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Use one of the points to find 'b'
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1 = -2*(-2) + b
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1 = 4 + b
b = -3
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y-intercept occurs when x=0, which is the point (0,-3).
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The equation in slope-intercept form is:
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y = -2x -3
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x-intercept occurs when y=0, so set y=0 and find x
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0 = -2x -3
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2x = -3
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x = -3/2
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So, the x-intercept = (-3/2, 0).
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A graph is always helpful.
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Answer by solver91311(24713)  (Show Source):
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