Question 47170This question is from textbook
: The length of a rectangle is 4 in. more than twice its width. If the perimeter of the rectangle is 26 in., find the width of the rectangle.
This question is from textbook
Answer by pizza(14)   (Show Source):
You can put this solution on YOUR website! This is a classic word problem. Best done via algebra, as follows.
Let l be the length of the rectangle, and w be the width.
So, we have two equations, that is,
eqn1: l = 2w + 4
eqn2: l + l + w + w = 26.
Finding the equations is supposed to be the hard step, now we try to solve it. Substitute eqn1 into eqn2 to get
(2w+4) + (2w+4) + w + w = 26
which simplifies to
6w + 8 = 26
which means w = 18/6 = 3.
which means l = 2x3 + 4 = 10.
|
|
|
