SOLUTION: Help please! The following problem has two solutions: 7^(x^2)=(7^5x)/(49^3) FYI,I know that the sum of the two solutions is 5. I just need a brush-up on some exponenti

Algebra ->  Test -> SOLUTION: Help please! The following problem has two solutions: 7^(x^2)=(7^5x)/(49^3) FYI,I know that the sum of the two solutions is 5. I just need a brush-up on some exponenti      Log On


   

Question 468207: Help please!
The following problem has two solutions:
7^(x^2)=(7^5x)/(49^3)
FYI,I know that the sum of the two solutions is 5.
I just need a brush-up on some exponential and logarithmic properties so I can know how to do this stuff, thanks!
J
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
7^(x^2)=(7^5x)/(49^3)
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7^(x^2) = (7^(5x)/(7^2)^3)
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7^x^2 = 7^(5x)/7^6
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7^(x^2) = 7^(5x-6)
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x^2 = 5x-6
x^2-5x+6 = 0
(x-6)(x+1) = 0
---
x = 6 or x = -1
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Cheers,
Stan H.
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