SOLUTION: The perimeter of a badminton court is 128 ft. After a game a badminton, a player's coach estimates that the athlete has run a total 444feet, which is equivalent to six times the co

Algebra ->  Test -> SOLUTION: The perimeter of a badminton court is 128 ft. After a game a badminton, a player's coach estimates that the athlete has run a total 444feet, which is equivalent to six times the co      Log On


   

Question 433514: The perimeter of a badminton court is 128 ft. After a game a badminton, a player's coach estimates that the athlete has run a total 444feet, which is equivalent to six times the courts length plus nine times it's width. What are the dimensions of a standard badminton court?
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Found 2 solutions by scott8148, jorel1380:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
2L + 2W = 128

6L + 9W = 444 ___ 2L + 3W = 148

subtracting equations ___ W = 20

substitute to find L

Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter=2Length+2Width
128=2L+2W
444=6L+9W
----------------
6L+9W=444
6L+6W=384
----------------
3W=60
W=20
L=44
The standard badminton court is 44'X 20'.
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++2%5Cx+%2B+2%5Cy+=+128%2C%0D%0A++++6%5Cx+%2B+9%5Cy+=+444+%29%0D%0A++

Any system of equations:


has solution

or



(x=44, y=20}