SOLUTION: find the distance between the points (12,8) and (4,2) 1. 100 units 2. 14 units 3. 10 units 4. -10 units Find the midpoint of the points (3,1) and (7,-5) 1. (1,6) 2. (2,1

Algebra ->  Test -> SOLUTION: find the distance between the points (12,8) and (4,2) 1. 100 units 2. 14 units 3. 10 units 4. -10 units Find the midpoint of the points (3,1) and (7,-5) 1. (1,6) 2. (2,1      Log On


   

Question 428529: find the distance between the points (12,8) and (4,2)
1. 100 units
2. 14 units
3. 10 units
4. -10 units
Find the midpoint of the points (3,1) and (7,-5)
1. (1,6)
2. (2,1)
3. (2,-3)
4. (5, -2)

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Distance between two points
x1 y1 x2 y2
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
12 8 4 2

d= sqrt%28%282-8%29%5E2%09%2B%284-12%29%5E2%29
d= sqrt%28%28-6%29%5E2%2B%28-8%29%5E2%29
d= sqrt%28%28100%29%5E2%09%29
d= 10
...
If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula
M =%28x1%2Bx2%29%2F2%28y1%2By2%29%2F2
( 3 , 1 ) ( 7 , -5 )
M = %28x1%2Bx2%29%2F2%09%09%09 %09%28y1%2By2%29%2F2
x= ( 3 + 7 )/ 2 y= ( 1 + 7 )/ 2
x= 5 y= 4