SOLUTION: I am working on equation of a line in slope-intercept form. One example I don't get is (10,7) are my points and 3/8 is what I am seeing. So it's y-(7)=3/8(x-(10)) then y-7=3\8x-15/

Algebra ->  Test -> SOLUTION: I am working on equation of a line in slope-intercept form. One example I don't get is (10,7) are my points and 3/8 is what I am seeing. So it's y-(7)=3/8(x-(10)) then y-7=3\8x-15/      Log On


   

Question 422513: I am working on equation of a line in slope-intercept form. One example I don't get is (10,7) are my points and 3/8 is what I am seeing. So it's y-(7)=3/8(x-(10)) then y-7=3\8x-15/4 then y=3/8x-15/4+28/4 then y= 3/8x+13/4 so my question is where does the 15/4 and the 28/4 come from?  Thanks!
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
you are given one point (10,7) and a slope 3%2F8; you need to find equation of a line that goes through given point and has a given slope

So it's
y-%287%29=3%2F8%28x-%2810%29%29 then
y-7=%283%2F8%29x-%283%2F8%29%2810%29%29.........reduce %283%2Fcross%288%294%29%28cross%2810%295%29%29=3%2A5%2F4=15%2F4
y-7=%283%2F8%29x-15%2F4%29..move -7 to the right
y=%283%2F8%29x-15%2F4%2B+7%29.....write 7 as a fraction with denominator 4 so you can subtract -15%2F4 from it.....7%2A4%2F4=28%2F4
y=%283%2F8%29x-15%2F4%2B+28%2F4%29...or
y=%283%2F8%29x%2B+%2828%2F4+-15%2F4%29%29
y=%283%2F8%29x%2B+%2828+-15%29%2F4%29

y=%283%2F8%29x%2B+13%2F4%29

+graph%28500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%283%2F8%29x%2B%2813%2F4%29%29%29+