SOLUTION: The sum of 3 integers is 123. The second number is two more than twice the first number. The third number is five less than the product of three and the first number. Find the thre

Algebra ->  Test -> SOLUTION: The sum of 3 integers is 123. The second number is two more than twice the first number. The third number is five less than the product of three and the first number. Find the thre      Log On


   



Question 396592: The sum of 3 integers is 123. The second number is two more than twice the first number. The third number is five less than the product of three and the first number. Find the three numbers
Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of 3 integers is 123. The second number is two more than twice the first number. The third number is five less than the product of three and the first number. Find the three numbers
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let the integers be x, y, z
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x+y+z=123...........................1
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y=2x+2...............................2
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z=3x-5...............................3
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plug value of y & z in equation (1)
x+2x+2+3x-5 =123
6x-3=123
6x=126
/6
x= 21
y= 2x+2= 44
z=58
..
21+44+58=123
...
m.ananth@hotmail.ca

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
call the integers a, b, and c
given:
a+%2B+b+%2B+c+=+123
b+=+2a+%2B+2
c+=+3a+-+5
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By substitution:
a+%2B+2a+%2B+2+%2B+3a+-+5+=+123
6a+-3+=+123
6a+=+126
a+=+21
and, since
b+=+2a+%2B+2
b+=+42+%2B+2
b+=+44
and
c+=+3a+-+5
c+=+63+-+5
c+=+58
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The integers are 21, 44, and 58