SOLUTION: 1. Express 3cos(x°)+5sin(x°) in the form kcos(x°-a°), where k>0 and 0≤a≤360
Can you provide full working with the solutions please.
Many Thanks,
Andrew.
Algebra ->
Test
-> SOLUTION: 1. Express 3cos(x°)+5sin(x°) in the form kcos(x°-a°), where k>0 and 0≤a≤360
Can you provide full working with the solutions please.
Many Thanks,
Andrew.
Log On
Question 388621: 1. Express 3cos(x°)+5sin(x°) in the form kcos(x°-a°), where k>0 and 0≤a≤360
Can you provide full working with the solutions please.
Many Thanks,
Andrew.
Draw a right triangle with those coefficients as legs:
horizontal leg = 3 and vertical leg = 5
Calculate the hypotenuse using the Pythagorean theorem
so so
Substitute for 3 and
substitute for 5 in
=
=
factor out on the left side:
=
Now we remember the formula , and the above can be written:
=
Since , the above becomes:
This is in the form
where and
So we have
= =
Edwin