SOLUTION: If 10^2x=25, what is the value of 10^-x?

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Question 378046: If 10^2x=25, what is the value of 10^-x?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
10%5E%282x%29+=+25. Take square roots of both sides to get 10%5Ex+=+5. (Discard 10%5Ex+=+-5 since the left-hand side is never negative.) THEN 10%5E%28-x%29+=+1%2F5, by taking reciprocals.