SOLUTION: Problem: our math class collected $1.25 in nickles and dimes. If there is a total of 15 coins, how many coins of each kind are there?

Algebra ->  Test -> SOLUTION: Problem: our math class collected $1.25 in nickles and dimes. If there is a total of 15 coins, how many coins of each kind are there?      Log On


   



Question 365201: Problem: our math class collected $1.25 in nickles and dimes. If there is a total of 15 coins, how many coins of each kind are there?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
n+d = 15,
0.05n + 0.10d = 1.25. The top equation gives d = 15-n. Substituting into the bottom equation, gives:
0.05n + 0.10(15-n) = 1.25,
0.05n + 1.5-0.10n = 1.25,
-0.05n = -0.25
n = 5, the number of nickels,
d = 10, the number of dimes.