SOLUTION: The point (-2,2) is a solution to the following linear system. Find the values for p and q. -5px+(7q-1)y=-4 (p+10)x-(4q+1)y=-32

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Question 359132: The point (-2,2) is a solution to the following linear system. Find the values for p and q.
-5px+(7q-1)y=-4
(p+10)x-(4q+1)y=-32
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

1)Substituting (-2,2)in the first equation

 -5p(-2)+(7q-1)*2=-4

10p+ 14q-2 =-4

10p+ 14q = -2



2)Substituting (-2,2)in the second equation

(p+10)(-2)-(4q+1)*2=-32

-20p - 8q - 2 = 32

-20p - 8q = 34

Multiplying first result by 2 and adding together

20p+ 28q = -4

-20p - 8q = 34

20q = 30

q = 3/2

10p + 21 = -2

p = -23/10

checking our answer

10*(-23/10) +14(3/2) = -23 + 21 = -2