SOLUTION: Need help with this problem. I need to find the Vertex, the line of symmetry, and the mas or minimum value of f(x) and then graph it.
f(x)= 1/5 (x+6)^2 +4
I appreciate your h
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-> SOLUTION: Need help with this problem. I need to find the Vertex, the line of symmetry, and the mas or minimum value of f(x) and then graph it.
f(x)= 1/5 (x+6)^2 +4
I appreciate your h
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Question 356175: Need help with this problem. I need to find the Vertex, the line of symmetry, and the mas or minimum value of f(x) and then graph it.
f(x)= 1/5 (x+6)^2 +4
I appreciate your help :o) Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
The equation is already in vertex form, where (,) is the vertex.
Comparing,
(,)=(,)
The vertex lies on the line of symmetry,
Since , the parabola opens upwards and the value at the vertex is the minimum.
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