SOLUTION: Suppose that x liters of 34% acid solution are mixed with y liters of a 44% solution to obtain 100 L of a 39% solution. One equation in a system for solving this problem is x+y=100

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Question 353435: Suppose that x liters of 34% acid solution are mixed with y liters of a 44% solution to obtain 100 L of a 39% solution. One equation in a system for solving this problem is x+y=100. What is the other equation?
Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose that x liters of 34% acid solution are mixed with y liters of a 44% solution to obtain 100 L of a 39% solution. One equation in a system for solving this problem is x+y=100. What is the other equation?
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x+y = 100 liters
0.34x + 0.44y = 0.39*100
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cheers,
Stan H.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x = 34%
y= 44%
mix= 100L 39%
...
x+y=100
0.34x+0.44y=100*0.39
....
m.ananth@hotmail.ca