SOLUTION: A trip of 1080 kms. Part way in car the avged 60 km/hr remainder on train travelling 100 km/hr. Entire trip was 12 hour. What distance travelled in each mode?

Algebra ->  Test -> SOLUTION: A trip of 1080 kms. Part way in car the avged 60 km/hr remainder on train travelling 100 km/hr. Entire trip was 12 hour. What distance travelled in each mode?      Log On


   

Question 335095: A trip of 1080 kms. Part way in car the avged 60 km/hr remainder on train travelling 100 km/hr. Entire trip was 12 hour. What distance travelled in each mode?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Rate*Time=Distance
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60%2AT1=D1
100%2AT2=D2
1.D1%2BD2=1080
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T1%2BT2=12
D1%2F60%2BD2%2F100=12
2.5D1%2B3D2=3600
From eq. 1,
D1=1080-D2
Substitute into eq. 2,
5%281080-D2%29%2B3D2=360
5400-5D2%2B3D2=3600
-2D2=-1800
highlight%28D2=900%29km
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D1%2B900=1080
highlight%28D1=180%29km