Question 326534: (3x^2-12-15)/(3x-9)
Answer by Apathious(24)   (Show Source):
You can put this solution on YOUR website! (3x^(2)-12-15)/(3x-9)
Subtract 15 from -12 to get -27.
(3x^(2)-27)/(3x-9)
Factor out the GCF of 3 from each term in the polynomial.
(3(x^(2))+3(-9))/(3x-9)
Factor out the GCF of 3 from 3x^(2)-27.
(3(x^(2)-9))/(3x-9)
The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
(3(x-3)(x+3))/(3x-9)
Factor out the GCF of 3 from each term in the polynomial.
(3(x-3)(x+3))/(3(x)+3(-3))
Factor out the GCF of 3 from 3x-9.
(3(x-3)(x+3))/(3(x-3))
Reduce the expression (3(x-3)(x+3))/(3(x-3)) by removing a factor of 3 from the numerator and denominator.
((x-3)(x+3))/(x-3)
Reduce the expression by canceling out the common factor of (x-3) from the numerator and denominator.
((x-3)(x+3))/((x-3))
Reduce the expression by canceling out the common factor of (x-3) from the numerator and denominator.
(x+3)
Remove the parentheses around the expression x+3.
x+3
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